[HOE] Drain vs. G-ray, voltage and impedance.

[Madnes6841@aol.com]

Hi List. I've got a question about Drain and G-ray. I've been examining the 
possibility of powering a Power Suit off a cyborg's spirit fetter(or a soul 
tap for that matter). I had a mild epiphany while examining the rules for 
Charging a Spirit Battery. 

First, the problem of powering a Power Suit. The Wolverine requires 1 G-ray 
per minute. If drain is truly equal to g-rays, then this is no problem.  
However, in order to put 1 g-ray into a spirit battery(let's say, a 10 point 
spirit battery), you need 1 drain continuosly for ten minutes. That equals 
120 drain.(1drain every five seconds, for a minute is 12 drain, times ten 
minutes) This leads to the first problem- Is that caused by an Impedance 
mismatch? As in, the voltage of a point of drain is 1/120th of the voltage of 
a G-ray, which would match up, in theory. But that wouldn't work, because 
according to Cyborgs, the larger a spirit battery is, the harder it is to 
charge with drain.(q.v., it has a higher impedance)  However, this is not 
true for a G-ray Collector charging a Spirit Battery- then, One G-ray 
colleced is One G-ray Charged.

So, What Is Drain? Is this voltage problem limited only to Spirit Batteries? 
Because if it isn't, it makes cyborgs effectively uselees when it comes to 
powering Junker equipment. The first forseeable answer is to find some way of 
Making a capacitator that can convert drain to G-rays, at a certain rate(like 
X drain=1 g-ray). Such a device would make it very easy for cyborgs to charge 
spirit batteries, because it would flatten the rate for charging. But, I'd 
like all of your analyses.

Uriah, the crazy gamer.